lib.strings.replaceStrings

Takes 3 arguments

from, to, s

Given string s, replace every occurrence of the strings in from with the corresponding string in to.

The argument to is lazy, that is, it is only evaluated when its corresponding pattern in from is matched in the string s

Example:

builtins.replaceStrings ["oo" "a"] ["a" "i"] "foobar"

evaluates to "fabir".

Noogle detected

• builtins.replaceStrings
• lib.replaceChars
• lib.replaceStrings
• lib.strings.replaceChars

replaceStrings :: [String] -> [String] -> String -> String