hasPrefix
lib.lists.hasPrefix
Docs pulled from | This Revision | 11 minutes ago
Whether the first list is a prefix of the second list.
Inputs
list1
-
1. Function argument
list2
-
2. Function argument
Type
hasPrefix :: [a] -> [a] -> bool
Examples
lib.lists.hasPrefix
usage example
hasPrefix [ 1 2 ] [ 1 2 3 4 ]
=> true
hasPrefix [ 0 1 ] [ 1 2 3 4 ]
=> false
Noogle detected
Implementation
The following is the current implementation of this function.
hasPrefix =
list1:
list2:
take (length list1) list2 == list1;