mergeAttrsList
lib.attrsets.mergeAttrsList
Docs pulled from | This Revision | about 1 hour ago
Merge a list of attribute sets together using the //
operator.
In case of duplicate attributes, values from later list elements take precedence over earlier ones.
The result is the same as foldl mergeAttrs { }
, but the performance is better for large inputs.
For n list elements, each with an attribute set containing m unique attributes, the complexity of this operation is O(nm log n).
Inputs
list
-
1. Function argument
Type
mergeAttrsList :: [ Attrs ] -> Attrs
Examples
lib.attrsets.mergeAttrsList
usage example
mergeAttrsList [ { a = 0; b = 1; } { c = 2; d = 3; } ]
=> { a = 0; b = 1; c = 2; d = 3; }
mergeAttrsList [ { a = 0; } { a = 1; } ]
=> { a = 1; }
Noogle detected
Implementation
The following is the current implementation of this function.
mergeAttrsList = list:
let
# `binaryMerge start end` merges the elements at indices `index` of `list` such that `start <= index < end`
# Type: Int -> Int -> Attrs
binaryMerge = start: end:
# assert start < end; # Invariant
if end - start >= 2 then
# If there's at least 2 elements, split the range in two, recurse on each part and merge the result
# The invariant is satisfied because each half will have at least 1 element
binaryMerge start (start + (end - start) / 2)
// binaryMerge (start + (end - start) / 2) end
else
# Otherwise there will be exactly 1 element due to the invariant, in which case we just return it directly
elemAt list start;
in
if list == [ ] then
# Calling binaryMerge as below would not satisfy its invariant
{ }
else
binaryMerge 0 (length list);